A box contains 5 red and 3 green balls. Two balls are drawn without replacement. Probability that both are red is: MCQ with Answer and Explanation

A box contains 5 red and 3 green balls. Two balls are drawn without replacement. Probability that both are red is:
A. (5/8)²
B. (5/8) × (4/7) = 5/14
C. (5/8) × (3/7)
D. (5/8) + (4/7)
Answer: Option B
Solution (By JKExamLibrary)
First red: 5/8, second red given first red: 4/7. Product = 20/56 = 5/14.

This question belongs to: Accountancy and Statistics Statistics

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