Assertion (A): Median is better than Mean for skewed distributions. Reason (R): Median is entirely immune to extreme values. MCQ with Answer and Explanation
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Question #1
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The mode of a continuous frequency distribution can be estimated using the formula:
Correct Answer: Option B
Explanation:
For grouped data, mode = L + [(f₁ - f₀) / (2f₁ - f₀ - f₂)] × h, where L=lower limit of modal class, f₁=frequency of modal class, f₀=previous class frequency, f₂=next class frequency, h=class width.
For grouped data, mode = L + [(f₁ - f₀) / (2f₁ - f₀ - f₂)] × h, where L=lower limit of modal class, f₁=frequency of modal class, f₀=previous class frequency, f₂=next class frequency, h=class width.
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Accountancy and Statistics
Statistics
Question #2
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In a frequency distribution, if the class midpoints are 10, 20, 30, 40, the class width is:
Correct Answer: Option D
Explanation:
Difference between consecutive midpoints = 10, so class width = 10.
Difference between consecutive midpoints = 10, so class width = 10.
This question belongs to:
Accountancy and Statistics
Statistics
Question #3
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An ogive is used to determine:
Correct Answer: Option B
Explanation:
The median can be read from the ogive at the N/2 cumulative frequency.
The median can be read from the ogive at the N/2 cumulative frequency.
This question belongs to:
Accountancy and Statistics
Statistics
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