A man faces north. He turns 90° left, then 180° right. Which direction? MCQ with Answer and Explanation

A man faces north. He turns 90° left, then 180° right. Which direction?
A. South
B. East
C. West
D. North
Answer: Option A
Solution (By JKExamLibrary)
N left 90° = West, right 180° = East? Wait: West (270°) + 180° = 90° East? Actually 270°+180°=450°=90° East. So East. Option B. I'll recalc: North -> left 90° -> West. Then 180° right from West: West (270°) +180° clockwise = 450° mod 360 = 90° East. So East. Answer East.

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Practice More Direction Sense Test Questions

Question #1
A child walks 1 km north, 2 km west, 1 km south. How far is he from start?
A. 3 km
B. 1 km
C. 0 km
D. 2 km

Correct Answer: Option D


Explanation:
North 1, west 2, south 1 -> net 2 km west.

This question belongs to: Reasoning Direction Sense Test
Question #2
A man travels 9 km west, then 12 km south, then 9 km east. Shortest distance?
A. 21 km
B. 15 km
C. 12 km
D. 9 km

Correct Answer: Option C


Explanation:
West-east cancel, 12 km south.

This question belongs to: Reasoning Direction Sense Test
Question #3
City Q is at a distance of 12 km to the south of city P. City R is 13 km to the north-west of city Q and west of city P. City S is 24 km to the south of city R. How far is city S from city Q and in which direction from it?
A. 13 km, south-west
B. 15 km, south
C. 14 km, north-east
D. 16 km, north

Correct Answer: Option A


Explanation:
Let P be (0,0). Q is (0,-12). R is West of P, so R is (x, 0). Distance R to Q is 13. By Pythagoras, x² + (-12)² = 13² -> x² + 144 = 169 -> x² = 25 -> x = -5 (West). So R is at (-5, 0). S is 24km South of R, so S is at (-5, -24). Distance from Q(0,-12) to S(-5,-24) -> Δx = -5, Δy = -12. Distance = √((-5)² + (-12)²) = 13km. S is West and South of Q

This question belongs to: Reasoning Direction Sense Test