Two stations A and B are 450 km apart. A train leaves station A at 4:00 PM at 60 km/h. Another train leaves station B at 5:00 PM at 70 km/h traveling towards A. At what time will they meet? MCQ with Answer and Explanation
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Question #1
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A commuter sets off from point M at 7 AM walking at 5 km/h. Another departs M at 9 AM in the same direction at 8 km/h. At what distance from M do they meet?
Correct Answer: Option D
Explanation:
By 9 AM, the first commuter has walked for 2 hours, covering 5 * 2 = 10 km. Relative speed = 8 - 5 = 3 km/h. Time taken to meet = 10 / 3 hours. Distance from M = Speed of second commuter * Time = 8 * (10/3) = 80/3 = 26.66 km.
By 9 AM, the first commuter has walked for 2 hours, covering 5 * 2 = 10 km. Relative speed = 8 - 5 = 3 km/h. Time taken to meet = 10 / 3 hours. Distance from M = Speed of second commuter * Time = 8 * (10/3) = 80/3 = 26.66 km.
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Maths
Time Speed and Distance
Question #2
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A man covers 3/5 of his total journey by rail at 40 km/h and the remaining 2/5 by bus at 30 km/h. If the total distance is 150 km, what is the total time taken?
Correct Answer: Option A
Explanation:
Distance by rail = 150 * (3/5) = 90 km. Time by rail = 90 / 40 = 2.25 hours. Distance by bus = 150 - 90 = 60 km. Time by bus = 60 / 30 = 2 hours. Total time = 2.25 + 2 = 4.25 hours.
Distance by rail = 150 * (3/5) = 90 km. Time by rail = 90 / 40 = 2.25 hours. Distance by bus = 150 - 90 = 60 km. Time by bus = 60 / 30 = 2 hours. Total time = 2.25 + 2 = 4.25 hours.
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Maths
Time Speed and Distance
Question #3
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The speed of a train is 20% more than the speed of a car. Both start from city P at the same time and reach city Q, 120 km away, at the same time. On the way, the train stops for 10 minutes at various stations. What is the speed of the car?
Correct Answer: Option B
Explanation:
Let car speed be c, then train speed is 1.2c. Time difference = 120/c - 120/(1.2c) = 10/60 hour = 1/6 hour. 120/c * (1 - 1/1.2) = 1/6 => 120/c * (0.2/1.2) = 1/6 => 120/c * (1/6) = 1/6 => c = 120 km/h.
Let car speed be c, then train speed is 1.2c. Time difference = 120/c - 120/(1.2c) = 10/60 hour = 1/6 hour. 120/c * (1 - 1/1.2) = 1/6 => 120/c * (0.2/1.2) = 1/6 => 120/c * (1/6) = 1/6 => c = 120 km/h.
This question belongs to:
Maths
Time Speed and Distance
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