The speed of a train is 20% more than the speed of a car. Both start from city P at the same time and reach city Q, 120 km away, at the same time. On the way, the train stops for 10 minutes at various stations. What is the speed of the car? MCQ with Answer and Explanation
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Question #1
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Walking at 6/7 of his typical speed, a clerk reaches his documentation terminal 14 minutes late. What is his typical time?
Correct Answer: Option B
Explanation:
New speed = 6/7 of typical speed => New time = 7/6 of typical time. Difference = 1/6 of typical time = 14 minutes. Typical time = 14 * 6 = 84 minutes.
New speed = 6/7 of typical speed => New time = 7/6 of typical time. Difference = 1/6 of typical time = 14 minutes. Typical time = 14 * 6 = 84 minutes.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A bicycle wheel of diameter 140 cm makes 300 revolutions in one minute. Find the speed of the bicycle in km/h.
Correct Answer: Option D
Explanation:
Radius r = 70 cm = 0.7 meters. Circumference = 2 * (22/7) * 0.7 = 4.4 meters. Distance in 1 minute = 300 * 4.4 = 1320 meters. Distance in 1 hour = 1320 * 60 = 79200 meters = 79.2 km. Speed = 79.2 km/h.
Radius r = 70 cm = 0.7 meters. Circumference = 2 * (22/7) * 0.7 = 4.4 meters. Distance in 1 minute = 300 * 4.4 = 1320 meters. Distance in 1 hour = 1320 * 60 = 79200 meters = 79.2 km. Speed = 79.2 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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Walking at 6/7 of his normal pace, a man is 12 minutes late to his workplace. What is his normal time?
Correct Answer: Option B
Explanation:
New speed = 6/7 of normal pace => New time = 7/6 of normal time. Difference = 1/6 of normal time = 12 minutes. Normal time = 12 * 6 = 72 minutes.
New speed = 6/7 of normal pace => New time = 7/6 of normal time. Difference = 1/6 of normal time = 12 minutes. Normal time = 12 * 6 = 72 minutes.
This question belongs to:
Maths
Time Speed and Distance
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