Time Speed and Distance MCQs
Practice Time, Speed and Distance MCQs with answers and detailed solutions. Learn train problems, boats and streams, relative speed, average speed, races, journeys and advanced quantitative aptitude questions for competitive examinations.
Question #1
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A car travels at a speed of 54 km/h. What is its speed expressed in meters per second?
Correct Answer: Option C
Explanation:
To convert km/h to m/s, multiply by 5/18. Speed = 54 * (5/18) = 3 * 5 = 15 m/s.
To convert km/h to m/s, multiply by 5/18. Speed = 54 * (5/18) = 3 * 5 = 15 m/s.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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An athlete runs a 200-meter race in 24 seconds. Find his speed in km/h.
Correct Answer: Option A
Explanation:
Speed in m/s = 200 / 24 = 25/3 m/s. To convert to km/h, multiply by 18/5. Speed = (25/3) * (18/5) = 5 * 6 = 30 km/h.
Speed in m/s = 200 / 24 = 25/3 m/s. To convert to km/h, multiply by 18/5. Speed = (25/3) * (18/5) = 5 * 6 = 30 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A cyclist covers a distance of 750 meters in 2 minutes 30 seconds. What is the speed of the cyclist in km/h?
Correct Answer: Option C
Explanation:
Time = 2 minutes + 30 seconds = 150 seconds. Speed = 750 / 150 = 5 m/s. Converting to km/h: 5 * (18/5) = 18 km/h.
Time = 2 minutes + 30 seconds = 150 seconds. Speed = 750 / 150 = 5 m/s. Converting to km/h: 5 * (18/5) = 18 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #4
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How long will a person take to walk around a square field of side 45 meters if his speed is 9 km/h?
Correct Answer: Option A
Explanation:
Perimeter of the square field = 4 * 45 = 180 meters. Speed = 9 km/h = 9 * (5/18) = 2.5 m/s. Time = Distance / Speed = 180 / 2.5 = 72 seconds.
Perimeter of the square field = 4 * 45 = 180 meters. Speed = 9 km/h = 9 * (5/18) = 2.5 m/s. Time = Distance / Speed = 180 / 2.5 = 72 seconds.
This question belongs to:
Maths
Time Speed and Distance
Question #5
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A train covers a distance of 360 km at a uniform speed. If the speed had been 10 km/h more, it would have taken 3 hours less for the same journey. What is the original speed of the train?
Correct Answer: Option D
Explanation:
Let original speed be s. 360/s - 360/(s+10) = 3. Dividing by 3: 120/s - 120/(s+10) = 1. 120(s + 10 - s) = s(s + 10) => 1200 = s(s + 10). Solving s^2 + 10s - 1200 = 0 gives (s-30)(s+40) = 0. Since speed is positive, s = 30 km/h.
Let original speed be s. 360/s - 360/(s+10) = 3. Dividing by 3: 120/s - 120/(s+10) = 1. 120(s + 10 - s) = s(s + 10) => 1200 = s(s + 10). Solving s^2 + 10s - 1200 = 0 gives (s-30)(s+40) = 0. Since speed is positive, s = 30 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #6
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A man covers a certain distance by car driving at 40 km/h and returns back to the starting point riding on a scooter at 10 km/h. Find his average speed for the whole journey.
Correct Answer: Option B
Explanation:
When equal distances are covered at two different speeds x and y, Average Speed = 2xy / (x + y). Here, Average Speed = (2 * 40 * 10) / (40 + 10) = 800 / 50 = 16 km/h.
When equal distances are covered at two different speeds x and y, Average Speed = 2xy / (x + y). Here, Average Speed = (2 * 40 * 10) / (40 + 10) = 800 / 50 = 16 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #7
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A person travels from P to Q at a speed of 30 km/h and returns from Q to P at a speed of 40 km/h. What is the ratio of time taken by him in the forward journey to that in the return journey?
Correct Answer: Option B
Explanation:
Since distance is constant, time is inversely proportional to speed. Ratio of times = Speed2 : Speed1 = 40 : 30 = 4:3.
Since distance is constant, time is inversely proportional to speed. Ratio of times = Speed2 : Speed1 = 40 : 30 = 4:3.
This question belongs to:
Maths
Time Speed and Distance
Question #8
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A person crosses a 600-meter long street in 5 minutes. What is his speed in km/h?
Correct Answer: Option B
Explanation:
Time = 5 minutes = 300 seconds. Speed = 600 / 300 = 2 m/s. Speed in km/h = 2 * (18/5) = 36 / 5 = 7.2 km/h.
Time = 5 minutes = 300 seconds. Speed = 600 / 300 = 2 m/s. Speed in km/h = 2 * (18/5) = 36 / 5 = 7.2 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #9
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Excluding stoppages, the speed of a bus is 54 km/h and including stoppages, it is 45 km/h. For how many minutes does the bus stop per hour?
Correct Answer: Option B
Explanation:
Stoppage time per hour = (Fast Speed - Slow Speed) / Fast Speed = (54 - 45) / 54 = 9 / 54 = 1/6 hour. In minutes = (1/6) * 60 = 10 minutes.
Stoppage time per hour = (Fast Speed - Slow Speed) / Fast Speed = (54 - 45) / 54 = 9 / 54 = 1/6 hour. In minutes = (1/6) * 60 = 10 minutes.
This question belongs to:
Maths
Time Speed and Distance
Question #10
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A thief is noticed by a policeman from a distance of 200 meters. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km/h and 11 km/h respectively. What is the distance between them after 6 minutes?
Correct Answer: Option B
Explanation:
Relative speed = 11 - 10 = 1 km/h = 1 * (5/18) = 5/18 m/s. Distance covered in 6 minutes (360 seconds) = (5/18) * 360 = 100 meters. Remaining distance = 200 - 100 = 100 meters.
Relative speed = 11 - 10 = 1 km/h = 1 * (5/18) = 5/18 m/s. Distance covered in 6 minutes (360 seconds) = (5/18) * 360 = 100 meters. Remaining distance = 200 - 100 = 100 meters.
This question belongs to:
Maths
Time Speed and Distance
