Time and Work MCQs
Practice Time and Work MCQs with answers and detailed solutions. Learn work efficiency, pipes and cisterns, men and women work problems, partnership, wages, productivity and advanced aptitude questions commonly asked in competitive exams.
Question #1
Report Error
A can complete a piece of work in 12 days, and B can complete the same work in 24 days. If they work together, how many days will it take them to complete the work?
Correct Answer: Option A
Explanation:
A's 1-day work = 1/12, B's 1-day work = 1/24. Combined 1-day work = 1/12 + 1/24 = 3/24 = 1/8. Therefore, they will complete the work together in 8 days.
A's 1-day work = 1/12, B's 1-day work = 1/24. Combined 1-day work = 1/12 + 1/24 = 3/24 = 1/8. Therefore, they will complete the work together in 8 days.
This question belongs to:
Maths
Time and Work
Question #2
Report Error
A and B together can do a piece of work in 6 days. If A alone can do it in 18 days, in how many days can B alone complete the work?
Correct Answer: Option C
Explanation:
Combined 1-day work = 1/6. A's 1-day work = 1/18. B's 1-day work = 1/6 - 1/18 = 2/18 = 1/9. Therefore, B alone can complete the work in 9 days.
Combined 1-day work = 1/6. A's 1-day work = 1/18. B's 1-day work = 1/6 - 1/18 = 2/18 = 1/9. Therefore, B alone can complete the work in 9 days.
This question belongs to:
Maths
Time and Work
Question #3
Report Error
A is twice as efficient as B. If they complete a piece of work together in 14 days, how many days will A alone take to finish it?
Correct Answer: Option A
Explanation:
Let B's efficiency be 1 unit/day, so A's efficiency is 2 units/day. Combined efficiency = 3 units/day. Total work = 3 * 14 = 42 units. Time taken by A alone = 42 / 2 = 21 days.
Let B's efficiency be 1 unit/day, so A's efficiency is 2 units/day. Combined efficiency = 3 units/day. Total work = 3 * 14 = 42 units. Time taken by A alone = 42 / 2 = 21 days.
This question belongs to:
Maths
Time and Work
Question #4
Report Error
12 men can complete a work in 8 days. How many days will 16 men take to complete the same work?
Correct Answer: Option A
Explanation:
Using the formula M1 * D1 = M2 * D2: 12 * 8 = 16 * D2. 96 = 16 * D2. D2 = 96 / 16 = 6 days.
Using the formula M1 * D1 = M2 * D2: 12 * 8 = 16 * D2. 96 = 16 * D2. D2 = 96 / 16 = 6 days.
This question belongs to:
Maths
Time and Work
Question #5
Report Error
A, B, and C can complete a work in 10, 12, and 15 days respectively. If they all work together, how long will they take to finish the work?
Correct Answer: Option B
Explanation:
Total work (LCM of 10, 12, 15) = 60 units. Efficiencies: A = 6, B = 5, C = 4. Total combined efficiency = 6 + 5 + 4 = 15 units/day. Time taken = 60 / 15 = 4 days.
Total work (LCM of 10, 12, 15) = 60 units. Efficiencies: A = 6, B = 5, C = 4. Total combined efficiency = 6 + 5 + 4 = 15 units/day. Time taken = 60 / 15 = 4 days.
This question belongs to:
Maths
Time and Work
Question #6
Report Error
A can do a piece of work in 10 days and B can do the same work in 15 days. If they work together, in how many days will the work be completed?
Correct Answer: Option B
Explanation:
A's 1-day work = 1/10, B's 1-day work = 1/15. Combined 1-day work = 1/10 + 1/15 = 5/30 = 1/6. Therefore, they will complete the work together in 6 days.
A's 1-day work = 1/10, B's 1-day work = 1/15. Combined 1-day work = 1/10 + 1/15 = 5/30 = 1/6. Therefore, they will complete the work together in 6 days.
This question belongs to:
Maths
Time and Work
Question #7
Report Error
A and B together can complete a piece of work in 4 days. If A alone can complete the same work in 12 days, in how many days can B alone complete it?
Correct Answer: Option A
Explanation:
Combined 1-day work = 1/4. A's 1-day work = 1/12. B's 1-day work = 1/4 - 1/12 = 2/12 = 1/6. Therefore, B alone can complete the work in 6 days.
Combined 1-day work = 1/4. A's 1-day work = 1/12. B's 1-day work = 1/4 - 1/12 = 2/12 = 1/6. Therefore, B alone can complete the work in 6 days.
This question belongs to:
Maths
Time and Work
Question #8
Report Error
A is twice as good a workman as B and together they finish a piece of work in 18 days. In how many days will A alone finish the work?
Correct Answer: Option A
Explanation:
Ratio of work done by A and B = 2:1. Let B's 1-day work be x, so A's 1-day work is 2x. Together, 3x = 1/18, which means x = 1/54. A's 1-day work = 2 * (1/54) = 1/27. Thus, A alone completes it in 27 days.
Ratio of work done by A and B = 2:1. Let B's 1-day work be x, so A's 1-day work is 2x. Together, 3x = 1/18, which means x = 1/54. A's 1-day work = 2 * (1/54) = 1/27. Thus, A alone completes it in 27 days.
This question belongs to:
Maths
Time and Work
Question #9
Report Error
A, B, and C can complete a piece of work in 12, 15, and 20 days respectively. In how many days will they finish it together?
Correct Answer: Option C
Explanation:
Total work = LCM of 12, 15, and 20 = 60 units. Efficiency of A = 5, B = 4, C = 3. Total efficiency = 5 + 4 + 3 = 12 units/day. Days required = 60 / 12 = 5 days.
Total work = LCM of 12, 15, and 20 = 60 units. Efficiency of A = 5, B = 4, C = 3. Total efficiency = 5 + 4 + 3 = 12 units/day. Days required = 60 / 12 = 5 days.
This question belongs to:
Maths
Time and Work
Question #10
Report Error
A can do a work in 20 days and B in 30 days. They work together for 7 days and then both leave. Then C alone finishes the remaining work in 10 days. In how many days will C alone finish the whole work?
Correct Answer: Option D
Explanation:
Total work = LCM(20, 30) = 60 units. Efficiency of A = 3, B = 2. Combined efficiency = 5 units/day. In 7 days, work done = 7 * 5 = 35 units. Remaining work = 60 - 35 = 25 units. C's efficiency = 25 units / 10 days = 2.5 units/day. Days for C to complete total work = 60 / 2.5 = 24 days.
Total work = LCM(20, 30) = 60 units. Efficiency of A = 3, B = 2. Combined efficiency = 5 units/day. In 7 days, work done = 7 * 5 = 35 units. Remaining work = 60 - 35 = 25 units. C's efficiency = 25 units / 10 days = 2.5 units/day. Days for C to complete total work = 60 / 2.5 = 24 days.
This question belongs to:
Maths
Time and Work
