A suspect flees at 6:00 AM at a uniform speed of 50 km/h. The enforcement squad tracks pursuit at 7:00 AM at 60 km/h. At what time will the squad apprehend the suspect?
Explanation:
By 7:00 AM, the suspect has traveled for 1 hour and covered 50 km. Relative tracking speed = 60 - 50 = 10 km/h. Time taken to catch = 50 / 10 = 5 hours. Apprehension time = 7:00 AM + 5 hours = 12:00 PM.
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