A ball is thrown vertically upward with velocity 49 m/s. Maximum height (g=9.8) is MCQ with Answer and Explanation

A ball is thrown vertically upward with velocity 49 m/s. Maximum height (g=9.8) is
A. 122.5 m
B. 245 m
C. 98 m
D. 490 m
Answer: Option A
Solution (By JKExamLibrary)
H = u²/(2g) = 2401/(19.6) = 122.5 m.

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Practice More Physics Questions

Question #1
The speed of light in vacuum is approximately
A. 3 × 10⁴ m/s
B. 3 × 10⁶ km/s
C. 3 × 10⁸ m/s
D. 3 × 10⁵ m/s

Correct Answer: Option C


Explanation:
3×10⁸ m/s = 3×10⁵ km/s.

This question belongs to: Science Physics
Question #2
A body covers 12 m in the 2nd second and 20 m in the 4th second of its motion. Assuming uniform acceleration, what is its initial velocity?
A. 4 m/s
B. 8 m/s
C. 2 m/s
D. 6 m/s

Correct Answer: Option D


Explanation:
The distance covered in the nth second is Sn = u + a/2 * (2n - 1). For n=2: 12 = u + a/2 * (3) => 2u + 3a = 24. For n=4: 20 = u + a/2 * (7) => 2u + 7a = 40. Subtracting equations: 4a = 16 => a = 4 m/s^2. Substitute 'a' back: 2u + 3(4) = 24 => 2u = 12 => u = 6 m/s.

This question belongs to: Science Physics
Question #3
A capillary tube is dipped in water and the water rises to a height 'h'. If the experiment is performed in a freely falling elevator, the water column in the tube will:
A. Not rise at all
B. Rise to the full length of the capillary tube
C. Rise to height h
D. Rise to height 2h

Correct Answer: Option B


Explanation:
The height of capillary rise is given by Jurin's law: h = 2Tcos(theta) / (rrhog). In a freely falling elevator, the effective acceleration due to gravity (g') is zero (weightlessness). As effective g approaches zero, the theoretical height h approaches infinity. In reality, the water will rise to the very top of the tube, regardless of its length, but will not overflow.

This question belongs to: Science Physics