A body covers 12 m in the 2nd second and 20 m in the 4th second of its motion. Assuming uniform acceleration, what is its initial velocity? MCQ with Answer and Explanation

A body covers 12 m in the 2nd second and 20 m in the 4th second of its motion. Assuming uniform acceleration, what is its initial velocity?
A. 8 m/s
B. 4 m/s
C. 2 m/s
D. 6 m/s
Answer: Option D
Solution (By JKExamLibrary)
The distance covered in the nth second is Sn = u + a/2 * (2n - 1). For n=2: 12 = u + a/2 * (3) => 2u + 3a = 24. For n=4: 20 = u + a/2 * (7) => 2u + 7a = 40. Subtracting equations: 4a = 16 => a = 4 m/s^2. Substitute 'a' back: 2u + 3(4) = 24 => 2u = 12 => u = 6 m/s.

This question belongs to: Science Physics

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