Walking at 6/7 of his normal pace, a man is 12 minutes late to his workplace. What is his normal time? MCQ with Answer and Explanation
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Question #1
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Walking at 6/7 of his typical speed, a clerk reaches his documentation terminal 14 minutes late. What is his typical time?
Correct Answer: Option B
Explanation:
New speed = 6/7 of typical speed => New time = 7/6 of typical time. Difference = 1/6 of typical time = 14 minutes. Typical time = 14 * 6 = 84 minutes.
New speed = 6/7 of typical speed => New time = 7/6 of typical time. Difference = 1/6 of typical time = 14 minutes. Typical time = 14 * 6 = 84 minutes.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A train 250 meters long takes 30 seconds to cross a man running at 6 km/h in the opposite direction. Find the speed of the train.
Correct Answer: Option B
Explanation:
Relative speed = 250 / 30 = 25/3 m/s = (25/3) * (18/5) = 30 km/h. In opposite directions, Relative Speed = Speed of train + Speed of man => 30 = Speed of train + 6 => Speed of train = 24 km/h.
Relative speed = 250 / 30 = 25/3 m/s = (25/3) * (18/5) = 30 km/h. In opposite directions, Relative Speed = Speed of train + Speed of man => 30 = Speed of train + 6 => Speed of train = 24 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A cyclist handles 600 meters in exactly 2 minutes. Find his moving velocity in km/h.
Correct Answer: Option C
Explanation:
Time = 2 minutes = 120 seconds. Speed = 600 / 120 = 5 m/s. In km/h = 5 * (18/5) = 18 km/h.
Time = 2 minutes = 120 seconds. Speed = 600 / 120 = 5 m/s. In km/h = 5 * (18/5) = 18 km/h.
This question belongs to:
Maths
Time Speed and Distance
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