An electric iron draws 5 A at 220 V. Its power is MCQ with Answer and Explanation

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An electric iron draws 5 A at 220 V. Its power is

A. 1100 W

B. 44 W

C. 2200 W

D. 550 W

Answer: Option A

Solution (By JKExamLibrary)

P = V×I = 220 × 5 = 1100 W = 1.1 kW. Energy consumed in 2 hours = 2.2 kWh. Simple.

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Question #1

Radioactive decay to 1/32 initial: number of half-lives:

A. 5

B. 6

C. 3

D. 4

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Correct Answer: Option A

Explanation:
(1/2)ⁿ = 1/32 ⇒ 2ⁿ = 32 ⇒ n = 5 half-lives. Exponential decay calculation. Memory aid: '1/2ⁿ remaining; 1/32 = 1/2⁵ ⇒ 5 half-lives'. Radioactivity arithmetic frequently tested in competitive exams.

This question belongs to: Science Physics

Question #2

Photoelectric threshold frequency ν₀ = φ/h. If work function doubles, ν₀:

A. Quadruples

B. Doubles

C. Unchanged

D. Halves

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Correct Answer: Option B

Explanation:
ν₀ ∝ φ. Double work function ⇒ double threshold frequency. Higher φ requires higher photon energy for emission. Memory tip: 'ν₀ = φ/h; larger φ ⇒ higher frequency needed'. Photoelectric effect relation frequently tested in competitive quantum physics sections.

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Question #3

Two resistance wires of same material and same length have diameters in ratio 2:1. Their resistances are in ratio

A. 1:2

B. 4:1

C. 1:4

D. 2:1

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Correct Answer: Option C

Explanation:
R ∝ L/A ∝ 1/d². So R₁/R₂ = (d₂/d₁)² = (1/2)² = 1/4 = 1:4.

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