A commuter sets off from point M at 7 AM walking at 5 km/h. Another departs M at 9 AM in the same direction at 8 km/h. At what distance from M do they meet? MCQ with Answer and Explanation
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Question #1
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Walking at 3/4 of his normal pace, a student is 12 minutes late. Find his usual time.
Correct Answer: Option A
Explanation:
New speed = 3/4 of usual speed => New time = 4/3 of usual time. Difference = 1/3 of usual time = 12 minutes. Usual time = 12 * 3 = 36 minutes.
New speed = 3/4 of usual speed => New time = 4/3 of usual time. Difference = 1/3 of usual time = 12 minutes. Usual time = 12 * 3 = 36 minutes.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A train 120 meters long passes a pole in 6 seconds. What is the speed of the train in km/h?
Correct Answer: Option B
Explanation:
Speed of train = 120 / 6 = 20 m/s. In km/h = 20 * (18/5) = 72 km/h.
Speed of train = 120 / 6 = 20 m/s. In km/h = 20 * (18/5) = 72 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A runner covers a 100-meter race. The winner finishes in 10 seconds while the runner-up finishes in 10.5 seconds. By what distance does the winner beat the runner-up?
Correct Answer: Option C
Explanation:
Speed of the runner-up = 100 / 10.5 = 200 / 21 m/s. Distance covered by the runner-up in 10 seconds = (200 / 21) * 10 = 2000 / 21 = 95.24 meters. Distance winner beats runner-up by = 100 - 95.24 = 4.76 meters.
Speed of the runner-up = 100 / 10.5 = 200 / 21 m/s. Distance covered by the runner-up in 10 seconds = (200 / 21) * 10 = 2000 / 21 = 95.24 meters. Distance winner beats runner-up by = 100 - 95.24 = 4.76 meters.
This question belongs to:
Maths
Time Speed and Distance
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