An individual with the genotype AaBb (if genes are unlinked) will produce how many types of gametes? MCQ with Answer and Explanation

An individual with the genotype AaBb (if genes are unlinked) will produce how many types of gametes?
A. 1
B. 4
C. 8
D. 2
Answer: Option B
Solution (By JKExamLibrary)
For an individual heterozygous at two unlinked loci (AaBb), the possible gamete combinations are AB, Ab, aB, ab, i.e., 4 types. This follows the law of independent assortment. Formula: 2^n, where n is the number of heterozygous gene pairs. Here n=2, so 2²=4. If genes are linked, recombination frequency determines the proportion.

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