If P(A) = 0.6, P(B) = 0.7, and P(A ∪ B) = 0.9, then P(A ∩ B) is: MCQ with Answer and Explanation

If P(A) = 0.6, P(B) = 0.7, and P(A ∪ B) = 0.9, then P(A ∩ B) is:
A. 0.2
B. 0.5
C. 0.4
D. 0.3
Answer: Option C
Solution (By JKExamLibrary)
By addition theorem: P(A∪B) = P(A) + P(B) - P(A∩B) → 0.9 = 0.6 + 0.7 - P(A∩B) → P(A∩B) = 1.3 - 0.9 = 0.4.

This question belongs to: Accountancy and Statistics Statistics

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For any two events A and B, P(A∪B) is:
A. Always ≤ 1
B. Always ≤ P(A) + P(B)
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Correct Answer: Option D


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By the addition rule, P(A∪B) ≤ P(A)+P(B), and probability of any event is ≤1.

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Question #2 Report Error
A frequency distribution with classes 10-20, 20-30, 30-40 … is called:
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Correct Answer: Option A


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The value that appears maximum number of times in a data set is called:
A. Mode
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Correct Answer: Option A


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Mode is the most frequent value.

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