If P(A)=0.7, P(B)=0.6, and P(A∪B)=0.9, then P(A∩B) is: MCQ with Answer and Explanation

If P(A)=0.7, P(B)=0.6, and P(A∪B)=0.9, then P(A∩B) is:
A. 0.4
B. 0.6
C. 0.3
D. 0.42
Answer: Option A
Solution (By JKExamLibrary)
P(A∩B) = P(A)+P(B)-P(A∪B) = 0.7+0.6-0.9 = 0.4.

This question belongs to: Accountancy and Statistics Statistics

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Practice More Statistics Questions

Question #1 Report Error
If P(A) = 0.6, P(B) = 0.3, and P(A ∩ B) = 0.18, then events A and B are:
A. Mutually exclusive
B. Dependent
C. Independent
D. Exhaustive

Correct Answer: Option C


Explanation:
Events are independent if P(A ∩ B) = P(A) × P(B). Here, 0.6 × 0.3 = 0.18, satisfying the condition.

This question belongs to: Accountancy and Statistics Statistics
Question #2 Report Error
The sum of squares of deviations from the mean is:
A. Zero
B. Equal to the variance
C. Maximum
D. Minimum

Correct Answer: Option D


Explanation:
The sum of squared deviations from the mean is minimum; from any other point it would be larger.

This question belongs to: Accountancy and Statistics Statistics
Question #3 Report Error
In the theory of attributes, the class frequency (AB) denotes:
A. Number of objects possessing both A and B
B. Number of objects not possessing A and B
C. Number of objects possessing attribute A only
D. Number of objects possessing attribute B only

Correct Answer: Option A


Explanation:
The notation (AB) represents the number of items possessing both attributes A and B.

This question belongs to: Accountancy and Statistics Statistics