If P(A)=0.7, P(B)=0.6, and the maximum possible value of P(A∩B) is 0.6, then the minimum possible value of P(A∪B) is: MCQ with Answer and Explanation

If P(A)=0.7, P(B)=0.6, and the maximum possible value of P(A∩B) is 0.6, then the minimum possible value of P(A∪B) is:
A. 0.8
B. 1.0
C. 0.6
D. 0.7
Answer: Option D
Solution (By JKExamLibrary)
P(A∪B) = P(A)+P(B)-P(A∩B). To minimize union, maximize intersection: max=0.6. So min union = 0.7+0.6-0.6=0.7.

This question belongs to: Accountancy and Statistics Statistics

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