In the reaction 3Cl2 + 6NaOH -> 5NaCl + NaClO3 + 3H2O, chlorine undergoes:
A. Neither oxidation nor reduction
B. Only reduction
C. Only oxidation
D. Both oxidation and reduction
Answer: Option D
Solution (By JKExamLibrary)
In this reaction, chlorine (oxidation state 0) reacts with hot, concentrated NaOH. It forms NaCl where Cl is -1 (reduction) and NaClO3 where Cl is +5 (oxidation). Since the same element, chlorine, is both oxidized and reduced, it undergoes a disproportionation reaction.
Explanation:
Dilute HNO₃ is an oxidizing agent; it oxidizes the hydrogen produced to water and itself gets reduced to nitrogen oxides (NO, N₂O, etc.). Very dilute HNO₃ with Mg/Mn can produce H₂. Metals above hydrogen normally displace H₂ from non-oxidizing acids like HCl.
Explanation:
Ozone decomposes quickly to O₂, leaving no residual disinfectant. Thus a small chlorine dose may be added after ozonation for distribution protection. Chlorine provides residual protection.
Explanation:
Saline water (containing NaCl) increases the electrical conductivity of the water, accelerating the electrochemical process of rusting. This is why ships and coastal structures rust faster. Dry air and vacuum have no moisture; pure water without dissolved oxygen slows rusting.
No comments yet. Be the first to start the discussion!