11 men can complete a work in 18 days. If 16 men work at the same rate, the work will be completed in: MCQ with Answer and Explanation
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Question #1
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A is twice as fast as B and B is thrice as fast as C. If C alone can complete the work in 24 days, in how many days can they together finish the work?
Correct Answer: Option C
Explanation:
Let efficiency of C = 1. Then efficiency of B = 3 * 1 = 3. Efficiency of A = 2 * 3 = 6. Total work = Efficiency of C * Time of C = 1 * 24 = 24 units. Combined efficiency of A, B and C = 6 + 3 + 1 = 10. Time taken together = 24 / 10 = 2.4 days.
Let efficiency of C = 1. Then efficiency of B = 3 * 1 = 3. Efficiency of A = 2 * 3 = 6. Total work = Efficiency of C * Time of C = 1 * 24 = 24 units. Combined efficiency of A, B and C = 6 + 3 + 1 = 10. Time taken together = 24 / 10 = 2.4 days.
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Maths
Time and Work
Question #2
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A and B together can do a piece of work in 9 days. If A does thrice the work of B in a given time, how many days will A alone take to complete the total work?
Correct Answer: Option D
Explanation:
Ratio of efficiency of A : B = 3 : 1. Combined efficiency = 3 + 1 = 4. Total work = 9 * 4 = 36 units. Time taken by A alone = 36 / 3 = 12 days.
Ratio of efficiency of A : B = 3 : 1. Combined efficiency = 3 + 1 = 4. Total work = 9 * 4 = 36 units. Time taken by A alone = 36 / 3 = 12 days.
This question belongs to:
Maths
Time and Work
Question #3
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A can do a work in 20 days and B in 30 days. They work together for 7 days and then both leave. Then C alone finishes the remaining work in 10 days. In how many days will C alone finish the whole work?
Correct Answer: Option B
Explanation:
Total work = LCM(20, 30) = 60 units. Efficiency of A = 3, B = 2. Combined efficiency = 5 units/day. In 7 days, work done = 7 * 5 = 35 units. Remaining work = 60 - 35 = 25 units. C's efficiency = 25 units / 10 days = 2.5 units/day. Days for C to complete total work = 60 / 2.5 = 24 days.
Total work = LCM(20, 30) = 60 units. Efficiency of A = 3, B = 2. Combined efficiency = 5 units/day. In 7 days, work done = 7 * 5 = 35 units. Remaining work = 60 - 35 = 25 units. C's efficiency = 25 units / 10 days = 2.5 units/day. Days for C to complete total work = 60 / 2.5 = 24 days.
This question belongs to:
Maths
Time and Work
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