13 men can complete a work in 17 days. If 17 men work at the same rate, in how many days will the work be completed? MCQ with Answer and Explanation
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Question #1
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If 20 men can build a wall 56 meters long in 6 days, what length of a similar wall can be built by 35 men in 3 days?
Correct Answer: Option B
Explanation:
Using (M1 * D1) / W1 = (M2 * D2) / W2: (20 * 6) / 56 = (35 * 3) / W2 => 120 / 56 = 105 / W2 => W2 = (105 * 56) / 120 = (7 * 56) / 8 = 7 * 7 = 49 meters.
Using (M1 * D1) / W1 = (M2 * D2) / W2: (20 * 6) / 56 = (35 * 3) / W2 => 120 / 56 = 105 / W2 => W2 = (105 * 56) / 120 = (7 * 56) / 8 = 7 * 7 = 49 meters.
This question belongs to:
Maths
Time and Work
Question #2
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A can complete a work in 18 days and B in 27 days. If they work together, the work will be completed in:
Correct Answer: Option A
Explanation:
Combined rate = 1/18 + 1/27. Required time = 10.8 days.
Combined rate = 1/18 + 1/27. Required time = 10.8 days.
This question belongs to:
Maths
Time and Work
Question #3
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A and B can complete a work in 10 days and 15 days respectively. They started together, but A left after some days and B finished the remaining work in 5 days. After how many days did A leave?
Correct Answer: Option B
Explanation:
Total work = LCM(10, 15) = 30 units. Efficiency of A = 3, B = 2. B worked alone for 5 days: work done = 5 * 2 = 10 units. Remaining work = 30 - 10 = 20 units. This was completed by A and B together. Combined efficiency = 3 + 2 = 5 units/day. Time they worked together = 20 / 5 = 4 days. Thus, A left after 4 days.
Total work = LCM(10, 15) = 30 units. Efficiency of A = 3, B = 2. B worked alone for 5 days: work done = 5 * 2 = 10 units. Remaining work = 30 - 10 = 20 units. This was completed by A and B together. Combined efficiency = 3 + 2 = 5 units/day. Time they worked together = 20 / 5 = 4 days. Thus, A left after 4 days.
This question belongs to:
Maths
Time and Work
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