16 men can complete a work in 14 days. If 20 men work at the same rate, in how many days will the work be completed? MCQ with Answer and Explanation
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Question #1
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A is 50% more efficient than B. If A can complete a piece of work in 12 days, in how many days can B complete the same work?
Correct Answer: Option B
Explanation:
Let efficiency of B = 2, then efficiency of A = 3. Total work = Efficiency of A * Time of A = 3 * 12 = 36 units. Time taken by B = 36 / 2 = 18 days.
Let efficiency of B = 2, then efficiency of A = 3. Total work = Efficiency of A * Time of A = 3 * 12 = 36 units. Time taken by B = 36 / 2 = 18 days.
This question belongs to:
Maths
Time and Work
Question #2
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A can do a work in 13 days and B in 23 days. In how many days will they complete 75% of the work together?
Correct Answer: Option A
Explanation:
Combined time for full work multiplied by 0.75 = 6.23 days.
Combined time for full work multiplied by 0.75 = 6.23 days.
This question belongs to:
Maths
Time and Work
Question #3
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X can do a piece of work in 24 days. When he had worked for 4 days, Y joined him. If complete work was finished in 14 days, Y alone can finish that work in:
Correct Answer: Option A
Explanation:
Let total work be 24 units. Efficiency of X = 1 unit/day. X worked for all 14 days, so work done by X = 14 * 1 = 14 units. Remaining work = 24 - 14 = 10 units. This 10 units of work was done by Y. Y worked for 14 - 4 = 10 days. So Y's efficiency = 10 / 10 = 1 unit/day. Time taken by Y alone = 24 / 1 = 24 days.
Let total work be 24 units. Efficiency of X = 1 unit/day. X worked for all 14 days, so work done by X = 14 * 1 = 14 units. Remaining work = 24 - 14 = 10 units. This 10 units of work was done by Y. Y worked for 14 - 4 = 10 days. So Y's efficiency = 10 / 10 = 1 unit/day. Time taken by Y alone = 24 / 1 = 24 days.
This question belongs to:
Maths
Time and Work
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