A, B and C can do a piece of work in 24, 30 and 40 days respectively. They began the work together but C left 4 days before the completion of the work. In how many days was the work completed?
Explanation:
Total work = LCM(24, 30, 40) = 120 units. Efficiencies: A = 5, B = 4, C = 3. Total efficiency = 12 units/day. Since C left 4 days before completion, add the work C would have done in those 4 days: 120 + (3 * 4) = 132 units. Total days = 132 / 12 = 11 days.
A can do a piece of work in 12 days and B in 15 days. They work together for 5 days and then B leaves. The days taken by A to finish the remaining work is:
Explanation:
Total work = LCM(12, 15) = 60 units. Efficiency of A = 5, B = 4. In 5 days, work done = 5 * (5 + 4) = 45 units. Remaining work = 60 - 45 = 15 units. Time taken by A to finish remaining work = 15 / 5 = 3 days.
No comments yet. Be the first to start the discussion!