A and B can complete a piece of work in 18 days and 24 days respectively. They worked together for 6 days and then A left. In how many days will B complete the remaining work?
Explanation:
Total work = LCM(18, 24) = 72 units. Efficiency of A = 4, B = 3. Combined efficiency = 7. In 6 days, work done = 6 * 7 = 42 units. Remaining work = 72 - 42 = 30 units. Time taken by B to finish remaining work = 30 / 3 = 10 days.
A, B and C can complete a piece of work in 10, 12 and 15 days respectively. They started the work together, but A left after 2 days and B left 3 days before the completion of the work. Find the total duration of the work.
Explanation:
Total work = LCM(10, 12, 15) = 60 units. Efficiency of A = 6, B = 5, C = 4. Let the work last for x days. A works for 2 days: work = 12 units. B works for (x - 3) days: work = 5(x - 3). C works for x days: work = 4x. Total work = 12 + 5x - 15 + 4x = 60 => 9x - 3 = 60 => 9x = 63 => x = 7 days.
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