8 men can complete a work in 18 days. If 12 men work at the same rate, in how many days will the work be completed? MCQ with Answer and Explanation
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Question #1
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A can finish a work in 18 days and B can do the same work in half the time taken by A. Then, working together, what part of the same work can they finish in a day?
Correct Answer: Option A
Explanation:
Time taken by A = 18 days, so B takes 9 days. Efficiency of A = 1/18, B = 1/9. Together in one day = 1/18 + 1/9 = 3/18 = 1/6.
Time taken by A = 18 days, so B takes 9 days. Efficiency of A = 1/18, B = 1/9. Together in one day = 1/18 + 1/9 = 3/18 = 1/6.
This question belongs to:
Maths
Time and Work
Question #2
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14 men can complete a work in 24 days. If 18 men work at the same rate, in how many days will the work be completed?
Correct Answer: Option B
Explanation:
Total work = 14 × 24 = 336 man-days. Required days = 336/18 = 18.67 days.
Total work = 14 × 24 = 336 man-days. Required days = 336/18 = 18.67 days.
This question belongs to:
Maths
Time and Work
Question #3
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A can do a work in 18 days and B in 24 days. They start together but A leaves 3 days before the completion of the work. Find the total number of days taken to complete the work.
Correct Answer: Option A
Explanation:
Total work = LCM(18, 24) = 72 units. Efficiency of A = 4, B = 3. Let total days be x. A works for (x - 3) days, B works for x days. 4(x - 3) + 3x = 72 => 4x - 12 + 3x = 72 => 7x = 84 => x = 12 days.
Total work = LCM(18, 24) = 72 units. Efficiency of A = 4, B = 3. Let total days be x. A works for (x - 3) days, B works for x days. 4(x - 3) + 3x = 72 => 4x - 12 + 3x = 72 => 7x = 84 => x = 12 days.
This question belongs to:
Maths
Time and Work
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