A and B are standing at a distance of 20 km from each other on a straight road running East-West. From there they start moving towards east and west at the same time. After covering a distance of 5 km, A turns to his left and walks 10 km, while B after covering a distance of 5 km turns to his right and walks 10 km at the same speed. After that both turn to their left and cover a distance of 5 km at the same speed. What is the distance between them now? MCQ with Answer and Explanation
A and B are standing at a distance of 20 km from each other on a straight road running East-West. From there they start moving towards east and west at the same time. After covering a distance of 5 km, A turns to his left and walks 10 km, while B after covering a distance of 5 km turns to his right and walks 10 km at the same speed. After that both turn to their left and cover a distance of 5 km at the same speed. What is the distance between them now?
A. 5 km
B. 20 km
C. 10 km
D. 25 km
Answer: Option C
Solution (By JKExamLibrary)
Assuming they start at x=0 and x=20 facing inwards. A goes 5 East (x=5), turns left (North) 10 (y=10), turns left (West) 5 (x=0, y=10). B goes 5 West (x=15), turns right (North) 10 (y=10), turns left (West) 5 (x=10, y=10). A is at (0, 10), B is at (10, 10). The distance is 10 km.
Jainav is initially facing a certain direction. Then she turns 90° clockwise, after that she turns 180° anticlockwise. Then she turns 135° anticlockwise. She finally turns 180° clockwise. Now she is facing north-east direction. In which direction was Jainav initially facing before turning?
Explanation:
Let clockwise turns be positive and anticlockwise be negative. Total turn = +90° - 180° - 135° + 180° = -45° (which means 45° anticlockwise). Her final direction is North-East. If she arrived at North-East after a 45° anticlockwise turn, her initial direction must have been East.
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