A and B can complete a work in 15 days and 10 days respectively. They started the work together but B left after 2 days. In how many days will A complete the remaining work? MCQ with Answer and Explanation
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Question #1
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A and B work together. A alone can complete the work in 24 days and B alone in 26 days. What percentage of the total daily work is contributed by A?
Correct Answer: Option C
Explanation:
A share = (1/24) / (1/24+1/26) ×100 = 52.0%.
A share = (1/24) / (1/24+1/26) ×100 = 52.0%.
This question belongs to:
Maths
Time and Work
Question #2
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A can do a work in 18 days and B in 24 days. They start together but A leaves 3 days before the completion of the work. Find the total number of days taken to complete the work.
Correct Answer: Option D
Explanation:
Total work = LCM(18, 24) = 72 units. Efficiency of A = 4, B = 3. Let total days be x. A works for (x - 3) days, B works for x days. 4(x - 3) + 3x = 72 => 4x - 12 + 3x = 72 => 7x = 84 => x = 12 days.
Total work = LCM(18, 24) = 72 units. Efficiency of A = 4, B = 3. Let total days be x. A works for (x - 3) days, B works for x days. 4(x - 3) + 3x = 72 => 4x - 12 + 3x = 72 => 7x = 84 => x = 12 days.
This question belongs to:
Maths
Time and Work
Question #3
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A is twice as fast as B and B is twice as fast as C. If they together can complete a work in 4 days, in how many days can C alone complete it?
Correct Answer: Option B
Explanation:
Let efficiency of C = 1, then B = 2 and A = 4. Combined efficiency = 1 + 2 + 4 = 7 units/day. Total work = 4 * 7 = 28 units. Time taken by C alone = 28 / 1 = 28 days.
Let efficiency of C = 1, then B = 2 and A = 4. Combined efficiency = 1 + 2 + 4 = 7 units/day. Total work = 4 * 7 = 28 units. Time taken by C alone = 28 / 1 = 28 days.
This question belongs to:
Maths
Time and Work
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