A and B can do a piece of work in 10 days, B and C in 12 days, and C and A in 15 days. How long will C alone take to complete the work? MCQ with Answer and Explanation

A and B can do a piece of work in 10 days, B and C in 12 days, and C and A in 15 days. How long will C alone take to complete the work?
A. 30 days
B. 24 days
C. 40 days
D. 60 days
Answer: Option C
Solution (By JKExamLibrary)
Total work = LCM(10, 12, 15) = 60 units. Efficiency of (A+B) = 6, (B+C) = 5, (C+A) = 4. Summing gives 2*(A+B+C) = 15 => Efficiency of (A+B+C) = 7.5. Efficiency of C = (A+B+C) - (A+B) = 7.5 - 6 = 1.5. Time taken by C alone = 60 / 1.5 = 40 days.

This question belongs to: Maths Time and Work

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Practice More Time and Work Questions

Question #1 Report Error
18 men can complete a work in 28 days. If 22 men work at the same rate, in how many days will the work be completed?
A. 26.91
B. 22.91
C. 28.91
D. 24.91

Correct Answer: Option B


Explanation:
Total work = 18 × 28 = 504 man-days. Required days = 504/22 = 22.91 days.

This question belongs to: Maths Time and Work
Question #2 Report Error
A and B work together. A alone can complete the work in 30 days and B alone in 34 days. What percentage of the total daily work is contributed by A?
A. 53.12
B. 55.62
C. 60.62
D. 58.12

Correct Answer: Option A


Explanation:
A share = (1/30) / (1/30+1/34) ×100 = 53.12%.

This question belongs to: Maths Time and Work
Question #3 Report Error
A group of men decided to do a work in 10 days, but 5 of them became absent. If the rest of the group did the work in 12 days, find the original number of men.
A. 40
B. 30
C. 25
D. 35

Correct Answer: Option B


Explanation:
Let the original number of men be x. Using M1 * D1 = M2 * D2: x * 10 = (x - 5) * 12 => 10x = 12x - 60 => 2x = 60 => x = 30.

This question belongs to: Maths Time and Work