A, B and C can do a piece of work in 24, 30 and 40 days respectively. They start together but C leaves 4 days before the completion of the work. In how many days was the work completed? MCQ with Answer and Explanation
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Question #1
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If 10 men or 20 women can do a piece of work in 13 days, in how many days will 24 men and 17 women complete the same work?
Correct Answer: Option A
Explanation:
10 Men = 20 Women => 1 Man = 2 Women. 24 men + 17 women = 24 * 2 + 17 = 48 + 17 = 65 women. Since 20 women do the work in 13 days, 65 women will do it in (20 * 13) / 65 = 260 / 65 = 4 days.
10 Men = 20 Women => 1 Man = 2 Women. 24 men + 17 women = 24 * 2 + 17 = 48 + 17 = 65 women. Since 20 women do the work in 13 days, 65 women will do it in (20 * 13) / 65 = 260 / 65 = 4 days.
This question belongs to:
Maths
Time and Work
Question #2
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15 men can complete a work in 22 days. If 20 men work at the same rate, the work will be completed in:
Correct Answer: Option A
Explanation:
Total work = 330 man-days. Time = 330/20 = 16.5 days.
Total work = 330 man-days. Time = 330/20 = 16.5 days.
This question belongs to:
Maths
Time and Work
Question #3
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A is twice as fast as B. If A and B together can complete a piece of work in 8 days, in how many days can A alone complete it?
Correct Answer: Option C
Explanation:
Let efficiency of B = 1, then efficiency of A = 2. Combined efficiency = 3 units/day. Total work = 8 * 3 = 24 units. Time taken by A alone = 24 / 2 = 12 days.
Let efficiency of B = 1, then efficiency of A = 2. Combined efficiency = 3 units/day. Total work = 8 * 3 = 24 units. Time taken by A alone = 24 / 2 = 12 days.
This question belongs to:
Maths
Time and Work
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