A ball is dropped from a height of 20 m. Time to reach ground (g=10) is MCQ with Answer and Explanation

A ball is dropped from a height of 20 m. Time to reach ground (g=10) is
A. 2 s
B. 4 s
C. 1 s
D. 3 s
Answer: Option A
Solution (By JKExamLibrary)
h = ½gt² => t = √(2h/g) = √(40/10) = √4 = 2 s. Free fall formula. Final velocity v = gt = 20 m/s.

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Practice More Physics Questions

Question #1
A car accelerates uniformly from rest to a speed of 72 km/h in 10 seconds. What is the distance covered during this time?
A. 100 m
B. 200 m
C. 400 m
D. 720 m

Correct Answer: Option A


Explanation:
First, convert speed to SI units: 72 km/h = 72 × (5/18) m/s = 20 m/s. Initial velocity (u) = 0, final velocity (v) = 20 m/s, time (t) = 10 s. Acceleration (a) = (v-u)/t = 20/10 = 2 m/s². Distance (s) = ut + (1/2)at² = 0 + 0.5 × 2 × 10² = 100 meters.

This question belongs to: Science Physics
Question #2
The material used for making solar cells is
A. Silicon
B. Copper
C. Iron
D. Aluminium

Correct Answer: Option A


Explanation:
Silicon semiconductor, abundant, efficient for photovoltaic cells. Also gallium arsenide. Solar cells convert light to electricity. Renewable energy technology.

This question belongs to: Science Physics
Question #3
A radioactive substance has half-life of 10 days. Fraction remaining after 30 days is
A. 1/4
B. 1/2
C. 1/8
D. 1/16

Correct Answer: Option C


Explanation:
Number of half-lives = 30/10 = 3. Remaining = (1/2)³ = 1/8. Exponential decay N = N₀(1/2)^(t/T). Radioactive decay constant λ = ln2/T.

This question belongs to: Science Physics