A ball is thrown vertically upward with speed 20 m/s. The maximum height reached (g = 10 m/s²) is
A. 20 m
B. 10 m
C. 40 m
D. 200 m
Answer: Option A
Solution (By JKExamLibrary)
Using v² = u² - 2gH, at maximum height v = 0. So 0 = 20² - 2×10×H => 400 = 20H => H = 20 m. Alternative formula: H = u²/(2g) = 400/20 = 20 m. Remember to use consistent units. For quick calculation, u²/(2g) is handy.
Explanation:
Pitch is subjective perception of frequency. Higher frequency higher pitch. Amplitude determines loudness. Speed and wavelength related by v = fλ, but pitch is frequency-based. Human ear 20 Hz-20 kHz.
Explanation:
Work done stored in electric field between plates: U = ½CV². Recoverable on discharge. Memory aid: 'Capacitor energy = ½CV² in electric field'. Electrostatics concept frequently tested in competitive exams.
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