A body of mass 2 kg is raised to height 10 m and dropped. Potential energy just before dropping is (g=10) MCQ with Answer and Explanation
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Question #1
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Work per unit charge to move between points is:
Correct Answer: Option D
Explanation:
Potential difference V = W/q: work per unit charge. Electric field E = F/q: force per unit charge. Memory tip: 'Potential = work/charge (scalar); Field = force/charge (vector)'. Electrostatics definition frequently tested in competitive exams.
Potential difference V = W/q: work per unit charge. Electric field E = F/q: force per unit charge. Memory tip: 'Potential = work/charge (scalar); Field = force/charge (vector)'. Electrostatics definition frequently tested in competitive exams.
Question #2
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The number of protons in an atom determines its
Question #3
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A positively charged particle is projected precisely parallel to a uniform magnetic field. The trajectory of the particle will be a:
Correct Answer: Option A
Explanation:
The magnetic Lorentz force on a moving charge is F = q(v x B) = qvBsin(theta). If the particle moves completely parallel to the magnetic field, the angle theta is 0 degrees. Since sin(0) = 0, the magnetic force is absolutely zero. Experiencing no transverse force, the particle continues moving in a perfect straight line.
The magnetic Lorentz force on a moving charge is F = q(v x B) = qvBsin(theta). If the particle moves completely parallel to the magnetic field, the angle theta is 0 degrees. Since sin(0) = 0, the magnetic force is absolutely zero. Experiencing no transverse force, the particle continues moving in a perfect straight line.
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