A body travels first half distance at speed v₁ and second half at v₂. Average speed is:
A. v₁v₂/(v₁+v₂)
B. (v₁+v₂)/2
C. 2v₁v₂/(v₁+v₂)
D. √(v₁v₂)
Answer: Option C
Solution (By JKExamLibrary)
For equal distances: average speed = total distance/total time = 2d/(d/v₁ + d/v₂) = 2v₁v₂/(v₁+v₂). This is harmonic mean, not arithmetic. Memory tip: Equal distances ⇒ harmonic mean of speeds; equal times ⇒ arithmetic mean. Frequently tested kinematics concept distinguishing average speed calculation methods.
Explanation:
v = u + at, linear relation, slope = a. Straight line inclined. If a=0, parallel to time axis (uniform velocity). Displacement-time is parabola for uniform acceleration.
No comments yet. Be the first to start the discussion!