A can complete a work in 11 days and B can complete the same work in 16 days. If they work together, in how many days will the work be completed? MCQ with Answer and Explanation
A, B and C can do a piece of work in 10, 12 and 15 days respectively. They began the work together but A left after 2 days and B left 3 days before the completion of the work. How long did the work last?
Explanation:
Total work = LCM(10, 12, 15) = 60 units. Efficiency of A = 6, B = 5, C = 4. Let the total time be x days. A worked for 2 days. B worked for (x - 3) days. C worked for x days. Total work = 2*6 + (x - 3)*5 + x*4 = 60 => 12 + 5x - 15 + 4x = 60 => 9x - 3 = 60 => 9x = 63 => x = 7 days.
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