Explanation:
10 Men = 20 Women => 1 Man = 2 Women. 24 men + 17 women = 24 * 2 + 17 = 48 + 17 = 65 women. Since 20 women do the work in 13 days, 65 women will do it in (20 * 13) / 65 = 260 / 65 = 4 days.
A and B can do a job in 12 days and 16 days respectively. Both work together for 3 days and then A leaves. How long will B take to complete the remaining work?
Explanation:
Total work = LCM(12, 16) = 48 units. Efficiency of A = 4, B = 3. Combined efficiency = 7 units/day. In 3 days, work completed = 7 * 3 = 21 units. Remaining work = 48 - 21 = 27 units. Time taken by B for remaining work = 27 / 3 = 9 days.
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