A can do a piece of work in 40 days. He works at it for 8 days and then B finishes it in 16 days. How long will A and B together take to complete the work? MCQ with Answer and Explanation
A can do a piece of work in 40 days. He works at it for 8 days and then B finishes it in 16 days. How long will A and B together take to complete the work?
A. 20 days
B. 13(1/3) days
C. 15 days
D. 25 days
Answer: Option B
Solution (By JKExamLibrary)
Let total work be 40 units. Efficiency of A = 1 unit/day. In 8 days, A completes 8 units. Remaining work = 40 - 8 = 32 units. B finishes 32 units in 16 days, so B's efficiency = 32 / 16 = 2 units/day. Combined efficiency of A and B = 1 + 2 = 3 units/day. Time taken together = 40 / 3 = 13(1/3) days.
Explanation:
Let efficiency of B = 2, then efficiency of A = 3. Total work = Efficiency of A * Time of A = 3 * 12 = 36 units. Time taken by B = 36 / 2 = 18 days.
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