A can finish a work in 12 days and B can do it in 15 days. After A had worked for 3 days, B also joined him to finish the remaining work. In how many days was the remaining work completed? MCQ with Answer and Explanation
A can finish a work in 12 days and B can do it in 15 days. After A had worked for 3 days, B also joined him to finish the remaining work. In how many days was the remaining work completed?
A. 5 days
B. 3 days
C. 4 days
D. 6 days
Answer: Option A
Solution (By JKExamLibrary)
Total work = LCM(12, 15) = 60 units. Efficiency of A = 5, B = 4. In 3 days, A completed 3 * 5 = 15 units. Remaining work = 60 - 15 = 45 units. Combined efficiency of A and B = 5 + 4 = 9 units/day. Time taken for remaining work = 45 / 9 = 5 days.
A and B can do a piece of work in 30 days and 36 days respectively. They began the work together but A left after some days and B finished the remaining work in 25 days. After how many days did A leave?
Explanation:
Total work = LCM(30, 36) = 180 units. Efficiency of A = 6, B = 5. B worked alone for 25 days: work done = 25 * 5 = 125 units. Remaining work = 180 - 125 = 55 units. This was completed by A and B together. Combined efficiency = 11. Days worked together = 55 / 11 = 5 days. Thus, A left after 5 days.
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