A car accelerates from rest at 2 m/s² for 10 s, then moves with constant velocity for 10 s. Total distance covered is MCQ with Answer and Explanation

A car accelerates from rest at 2 m/s² for 10 s, then moves with constant velocity for 10 s. Total distance covered is
A. 100 m
B. 300 m
C. 200 m
D. 400 m
Answer: Option B
Solution (By JKExamLibrary)
Acceleration phase: s₁ = ½a t² = ½×2×100 = 100 m, v = a t = 20 m/s. Constant velocity phase: s₂ = v×t = 20×10 = 200 m. Total = 300 m. Motion in two parts.

This question belongs to: Science Physics

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