A car accelerates uniformly from 18 km/h to 36 km/h in 5 seconds. The distance covered is
A. 45 m
B. 75 m
C. 54 m
D. 37.5 m
Answer: Option D
Solution (By JKExamLibrary)
Convert speeds: 18 km/h = 5 m/s, 36 km/h = 10 m/s. Using v = u + at => a = (10-5)/5 = 1 m/s². Distance s = ut + ½at² = 5×5 + ½×1×25 = 25 + 12.5 = 37.5 m. Also using average velocity: (5+10)/2 × 5 = 7.5×5 = 37.5 m. Answer A.
Explanation:
Torque τ = r×F: [L][MLT⁻²] = [ML²T⁻²]. Work W = F·d: same dimensions. Physically distinct: torque (vector, rotational), work (scalar, energy). Memory tip: 'Torque and work: same [ML²T⁻²]; different physical meaning'. Dimensional analysis frequently tested in competitive exams.
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