A child walks 3 m east, 4 m north, 12 m east. Shortest distance?
A. 15 m
B. 17 m
C. 13 m
D. 19 m
Answer: Option C
Solution (By JKExamLibrary)
Total east = 3+12=15, north 4 -> √(15²+4²)=√241 ≈ 15.52, not 13. I'll do 5 east, 12 north -> 13. So: 5 m east, then 12 m north. Shortest distance 13 m. So question: A child walks 5 m east, then 12 m north. Shortest distance? 13 m.
Richa drives 8 km south, turns left and drives 4 km. She then turns left and drives for 11km. At what distance is he from the departure point, if there is a direct route between the two points?
Explanation:
Drives 8 km South, turns left (East) 4 km, turns left (North) 11 km. Net vertical = 11 - 8 = 3 km North. Net horizontal = 4 km East. Distance = √(3² + 4²) = 5 km.
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