A child walks 5 m east, then 12 m north. What is the shortest distance from start? MCQ with Answer and Explanation

A child walks 5 m east, then 12 m north. What is the shortest distance from start?
A. 11 m
B. 13 m
C. 15 m
D. 17 m
Answer: Option B
Solution (By JKExamLibrary)
√(5²+12²)=13 m.

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Practice More Direction Sense Test Questions

Question #1
A girl faces north. She turns 135° clockwise, then 90° anticlockwise. Which direction?
A. North-west
B. South-east
C. North-east
D. South-west

Correct Answer: Option C


Explanation:
N (0°) +135° = 135° SE, -90° = 45° NE.

This question belongs to: Reasoning Direction Sense Test
Question #2
Vineet cycles 8 km south, then turns west and cycles 9 km, then turns north and cycles 6 km, then turns east and cycles 5 km, then turns to his left and cycles 2 km. Where is he now with respect to his starting position?
A. 4 km west
B. 4 km east
C. 13 km west
D. 13 km east

Correct Answer: Option A


Explanation:
South 8, west 9, north 6, east 5, left (north) 2. Net: south 8 - north 6+2 = 0; west 9 - east 5 = 4 km west. So 4 km west.

This question belongs to: Reasoning Direction Sense Test
Question #3
In a playground Anand, Bhaskaran, Chinni, David and Edward are facing north and are standing as given below.
I. Bhaskaran is to the right of David at a distance of 40 metres.
II. Anand is 60 meters to the south of Bhaskaran.
III. Chinni is 25 meters to the west of David.
IV. Edward is 90 meters to the north of Anand.
Who is to the North-East of the person, who is to the left of Bhaskaran?
A. Edward
B. david
C. Chitri
D. aanand

Correct Answer: Option A


Explanation:
David is to the left of Bhaskaran. Using David as origin (0,0): Bhaskaran is at (40, 0). Anand is 60m South of Bhaskaran at (40, -60). Edward is 90m North of Anand at (40, 30). With David at (0,0) and Edward at (40, 30), Edward is directly North-East of David.

This question belongs to: Reasoning Direction Sense Test