A fuse in an electrical circuit is designed to: MCQ with Answer and Explanation
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Question #1
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The work done in moving a charge of 2 C between two points with potential difference of 12 V is:
Correct Answer: Option B
Explanation:
Work done W = charge (Q) × potential difference (V). Thus W = 2 C × 12 V = 24 J. This follows from definition of voltage: 1 volt = 1 joule per coulomb. The work done equals the change in electrical potential energy. This fundamental relationship is crucial in electricity. Memory tip: W = QV is analogous to mechanical work = force × distance. Such direct formula applications are common in competitive exams to test basic concept retention. Always verify units: coulomb × volt = joule, confirming dimensional consistency.
Work done W = charge (Q) × potential difference (V). Thus W = 2 C × 12 V = 24 J. This follows from definition of voltage: 1 volt = 1 joule per coulomb. The work done equals the change in electrical potential energy. This fundamental relationship is crucial in electricity. Memory tip: W = QV is analogous to mechanical work = force × distance. Such direct formula applications are common in competitive exams to test basic concept retention. Always verify units: coulomb × volt = joule, confirming dimensional consistency.
Question #2
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The moment of inertia of a thin rod of mass M and length L about an axis through its centre and perpendicular to length is
Question #3
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The time period of a simple pendulum on Earth is T. If taken to a planet where g is 4 times, new period is
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