A fuse wire is connected in which wire? MCQ with Answer and Explanation
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Question #1
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If the error in the measurement of the momentum of a particle is +100%, what will be the percentage error in the measurement of its kinetic energy?
Correct Answer: Option D
Explanation:
Kinetic Energy (K) is given by K = p^2 / 2m. If momentum (p) increases by 100%, the new momentum is p' = p + 1.0p = 2p. The new kinetic energy is K' = (2p)^2 / 2m = 4(p^2 / 2m) = 4K. The increase is 4K - K = 3K. Percentage increase = (3K/K) * 100 = 300%.
Kinetic Energy (K) is given by K = p^2 / 2m. If momentum (p) increases by 100%, the new momentum is p' = p + 1.0p = 2p. The new kinetic energy is K' = (2p)^2 / 2m = 4(p^2 / 2m) = 4K. The increase is 4K - K = 3K. Percentage increase = (3K/K) * 100 = 300%.
Question #2
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According to Wien's Displacement Law, if the absolute temperature of a radiating black body is doubled, the wavelength corresponding to maximum spectral emissive power will:
Correct Answer: Option C
Explanation:
Wien's Displacement Law states that the wavelength at which a black body emits maximum radiation (lambda_m) is inversely proportional to its absolute temperature (T). lambda_m * T = b (Wien's constant). If the temperature T is doubled (2T), the peak wavelength lambda_m must strictly halve to maintain the constant product.
Wien's Displacement Law states that the wavelength at which a black body emits maximum radiation (lambda_m) is inversely proportional to its absolute temperature (T). lambda_m * T = b (Wien's constant). If the temperature T is doubled (2T), the peak wavelength lambda_m must strictly halve to maintain the constant product.
Question #3
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The maximum displacement of a particle from mean position in SHM is called
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