A is 50% more efficient than B. C does half of the work done by A and B together in the same time. If C alone can do the work in 40 days, then A, B and C together can do the work in: MCQ with Answer and Explanation
A is 50% more efficient than B. C does half of the work done by A and B together in the same time. If C alone can do the work in 40 days, then A, B and C together can do the work in:
A. 20 days
B. 15 days
C. 13(1/3) days
D. 30 days
Answer: Option C
Solution (By JKExamLibrary)
Let efficiency of B = 2, then efficiency of A = 3. Combined efficiency of A and B = 5. Efficiency of C = 5 / 2 = 2.5. Total work = Efficiency of C * Time taken by C = 2.5 * 40 = 100 units. Combined efficiency of A, B and C = 3 + 2 + 2.5 = 7.5 units/day. Time taken together = 100 / 7.5 = 1000 / 75 = 40 / 3 = 13(1/3) days.
Explanation:
Total work = LCM(20, 30) = 60 units. Efficiency of A = 3, B = 2. In a 2-day cycle (A then B), work completed = 3 + 2 = 5 units. Number of cycles required = 60 / 5 = 12 cycles. Total time = 12 * 2 = 24 days.
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