A machine gun fires 60 bullets per minute, each of mass 10 g with velocity 600 m/s. The power developed by the gun is:
A. 18000 W
B. 300 W
C. 1800 W
D. 3000 W
Answer: Option C
Solution (By JKExamLibrary)
Power = work done per unit time = kinetic energy imparted per second. KE per bullet = ½mv² = ½×0.01×(600)² = 1800 J. Bullets per second = 60/60 = 1. Thus power = 1800 J/s = 1800 W. Note: Mass conversion: 10 g = 0.01 kg. This problem combines kinetic energy formula with power definition. Exam tip: Always convert to SI units first (grams to kg, minutes to seconds). Such numerical problems test multi-step calculation skills and unit conversion proficiency essential for competitive examinations.
Explanation:
In Simple Harmonic Motion (like a swinging pendulum), velocity is maximum when the particle passes through its equilibrium or mean position. Since Kinetic Energy = ½mv², KE is maximum at the mean position. At the extreme positions, the velocity is briefly zero, meaning kinetic energy is zero and potential energy is maximum.
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