A man starts walking towards South and after taking a left turn he walks 30 metres. If he was then at a distance of 50 meters from the starting point, how much distance had he covered before turning to the left? MCQ with Answer and Explanation

Explanation:
Net 7 km west.

Explanation:
Let P be (0,0). Q is (0,-12). R is West of P, so R is (x, 0). Distance R to Q is 13. By Pythagoras, x² + (-12)² = 13² -> x² + 144 = 169 -> x² = 25 -> x = -5 (West). So R is at (-5, 0). S is 24km South of R, so S is at (-5, -24). Distance from Q(0,-12) to S(-5,-24) -> Δx = -5, Δy = -12. Distance = √((-5)² + (-12)²) = 13km. S is West and South of Q

Explanation:
West 6, right (north) 8, right (east) 6 -> net north 8 km.