A man walks 2 km south, turns left and walks 2 km, turns left and walks 2 km. How far from start? MCQ with Answer and Explanation

A man walks 2 km south, turns left and walks 2 km, turns left and walks 2 km. How far from start?
A. 2 km
B. 0 km
C. 4 km
D. 2√2 km
Answer: Option A
Solution (By JKExamLibrary)
South 2, left (east) 2, left (north) 2 -> north-south cancel, 2 km east.

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Practice More Direction Sense Test Questions

Question #1
Sundar walks 4 km towards east. Then he turns right and walks 3 km. Again he turns to the right and continues walking. Which direction is he going now?
A. North
B. East
C. West
D. South

Correct Answer: Option C


Explanation:
East 4, right (south) 3, right (west). He is now walking west.

This question belongs to: Reasoning Direction Sense Test
Question #2
Vinayak walks 5m in South and then he turns to his left and walks 12m. After that he again turns towards south and walks 8 metres. Then he turns to his right and walks 15 metres. In which direction is Vinayak now with respect to his starting point?
A. South
B. northeast
C. North
D. Southwest

Correct Answer: Option D


Explanation:
Path: 5m South, 12m East (left turn), 8m South, 15m West (right turn). Total South = 5 + 8 = 13m. Total West = 15 - 12 = 3m. Since he is South and West of his origin, he is in the South-West direction.

This question belongs to: Reasoning Direction Sense Test
Question #3
A person walks 20 m in the east. Walked and turned 90° clockwise and walked 20 m. walked. From there he again turns to his left and walks 10 m. Then he turned 90° anticlockwise and walked 20 m. walked. How far and in which direction is he from the starting point?
A. 30 m. East
B. 30 m. North
C. 30 m. South
D. 25 m. East

Correct Answer: Option A


Explanation:
Walks 20 m East. Turns 90° CW (South) for 20 m. Turns left (East) for 10 m. Turns 90° CCW (North) for 20 m. The 20 m South and 20 m North cancel each other. Total horizontal distance = 20 m East + 10 m East = 30 m East.

This question belongs to: Reasoning Direction Sense Test