A man starts walking towards South and after taking a left turn he walks 30 metres. If he was then at a distance of 50 meters from the starting point, how much distance had he covered before turning to the left?
Explanation:
This forms a right triangle where the final hypotenuse distance is 50m, and one leg (the horizontal walk) is 30m. The vertical walk (y) is found using Pythagoras: y² + 30² = 50² -> y² + 900 = 2500 -> y² = 1600 -> y = 40m.
Sam walks 10 m towards west from his house and turns left and walks 5 m. After this he turns left and walks 10 m and finally turns left and walks 10 m. In which direction is he from the starting point now?
Explanation:
Sam walks 10 m West, then turns left (South) for 5 m, turns left (East) for 10 m (aligning horizontally with his house), and turns left (North) for 10 m. He ends up 5 m North of his starting point.
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