A ship floats because its density is MCQ with Answer and Explanation

A ship floats because its density is
A. Greater than water
B. Zero
C. Equal to water
D. Less than water on average
Answer: Option D
Solution (By JKExamLibrary)
Ship is made of steel (density > water) but hollow shape makes average density (including air) less than water. Displaced water weight equals ship's weight, buoyancy holds it up.

This question belongs to: Science Physics

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Practice More Physics Questions

Question #1 Report Error
A body at 100°C is placed in contact with a body at 0°C. Heat flow stops when
A. Both reach 100°C
B. Both reach 0°C
C. Heat content becomes equal
D. Thermal equilibrium is reached

Correct Answer: Option D


Explanation:
Heat flows until temperatures equal, i.e., thermal equilibrium. Not necessarily 50°C unless heat capacities equal.

This question belongs to: Science Physics
Question #2 Report Error
The work function of a metal is 2.3 eV. The threshold frequency for photoelectric emission is approximately: (h = 4.14×10⁻¹⁵ eV·s)
A. 8.0×10¹⁴ Hz
B. 1.2×10¹⁵ Hz
C. 5.6×10¹⁴ Hz
D. 3.5×10¹⁴ Hz

Correct Answer: Option C


Explanation:
Photoelectric equation: work function φ = hν₀, where ν₀ is threshold frequency. Thus ν₀ = φ/h = 2.3 eV / (4.14×10⁻¹⁵ eV·s) ≈ 5.555×10¹⁴ Hz ≈ 5.6×10¹⁴ Hz. This direct application tests photoelectric effect fundamentals. Memory aid: 'ν₀ = φ/h; higher work function ⇒ higher threshold frequency'. Competitive exams frequently provide h in eV·s for such calculations. Always ensure units match: eV for φ and h to avoid conversion errors. This problem assesses numerical proficiency in modern physics applications.

This question belongs to: Science Physics
Question #3 Report Error
What is the magnetic dipole moment of an electron revolving in a circular orbit of radius 'r' with a uniform speed 'v'?
A. e / (vr)
B. evr / 2
C. evr
D. 2evr

Correct Answer: Option B


Explanation:
Magnetic dipole moment M = Current(I) * Area(A). Current is charge/time: I = e / T. Time period T = 2pir / v. So I = ev / (2pir). The area of the circular orbit is A = pir^2. Therefore, M = [ev / (2pir)] * [pir^2] = evr / 2. This is a standard derivation in modern physics.

This question belongs to: Science Physics