A train starts from Delhi at 6:00 AM and reaches Ambala at 10:00 AM. Another train starts from Ambala at 8:00 AM and reaches Delhi at 11:30 AM. At what time do the two trains cross each other? MCQ with Answer and Explanation

A train starts from Delhi at 6:00 AM and reaches Ambala at 10:00 AM. Another train starts from Ambala at 8:00 AM and reaches Delhi at 11:30 AM. At what time do the two trains cross each other?
A. 8:56 AM
B. 9:36 AM
C. 9:24 AM
D. 9:12 AM
Answer: Option A
Solution (By JKExamLibrary)
Train 1 takes 4 hours, Train 2 takes 3.5 hours (7/2 hours). Let distance be LCM(4, 3.5) = 28 units. Speed of Train 1 = 7 units/h, Speed of Train 2 = 8 units/h. By 8:00 AM, Train 1 travels 2 hours * 7 = 14 units. Remaining distance = 28 - 14 = 14 units. Relative speed = 7 + 8 = 15 units/h. Time to meet after 8 AM = 14/15 hours = 56 minutes. Meeting time = 8:56 AM.

This question belongs to: Maths Time Speed and Distance

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Practice More Time Speed and Distance Questions

Question #1 Report Error
A train 110 meters long crosses a pole in 5.5 seconds. What is its speed in km/h?
A. 64 km/h
B. 80 km/h
C. 84 km/h
D. 72 km/h

Correct Answer: Option D


Explanation:
Speed of train = 110 / 5.5 = 20 m/s. In km/h = 20 * (18/5) = 72 km/h.

This question belongs to: Maths Time Speed and Distance
Question #2 Report Error
Walking at 7/8 of his usual speed, a person reaches his office 10 minutes late. Find his usual time to reach the office.
A. 70 minutes
B. 90 minutes
C. 80 minutes
D. 60 minutes

Correct Answer: Option A


Explanation:
New speed = 7/8 of usual speed => New time = 8/7 of usual time. Difference = 1/7 of usual time = 10 minutes. Usual time = 10 * 7 = 70 minutes.

This question belongs to: Maths Time Speed and Distance
Question #3 Report Error
A man can row 9 km/h in still water. He rows to a place 24 km away and back in a total of 6 hours. Find the speed of the river current.
A. 2 km/h
B. 4 km/h
C. 5 km/h
D. 3 km/h

Correct Answer: Option D


Explanation:
Let speed of current be c. 24 / (9 + c) + 24 / (9 - c) = 6. Dividing by 6: 4 / (9 + c) + 4 / (9 - c) = 1 => 4(9 - c + 9 + c) = 81 - c^2 => 72 = 81 - c^2 => c^2 = 9 => c = 3 km/h.

This question belongs to: Maths Time Speed and Distance