A tuning fork of frequency 256 Hz is struck and held near a closed organ pipe. Resonance occurs when pipe length is approx (v=340 m/s) MCQ with Answer and Explanation

A tuning fork of frequency 256 Hz is struck and held near a closed organ pipe. Resonance occurs when pipe length is approx (v=340 m/s)
A. 66 cm
B. 33 cm
C. 50 cm
D. 17 cm
Answer: Option B
Solution (By JKExamLibrary)
For closed pipe fundamental: L = v/(4f) = 340/(4×256) ≈ 340/1024 ≈ 0.332 m = 33 cm.

This question belongs to: Science Physics

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